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# How to calculate marks from percentile in JEE Main 2020

National testing agency releases the result, which comprises of the percentile. Candidates obtain the percentile on the basis of their performance in the examination. However, it is easy to calculate the marks from percentile. On this page, we are discussing how to calculate marks from percentile in JEE Main 2020. Percentile scores are scores based on the relative performance of all candidates who appear for the examination. The marks obtained are transformed into a scale ranging from 100 to zero for each session. NTA uses the percentile concept so that normalization procedure can be carried out for compiling the scores for multi session papers.

JEE Main Result 2020 will be announced by the NTA on January 31. The exam was held on January 6, 7, 8, and 9, 2020.

Calculate marks from percentile in JEE Main 2020

NTA normalizes the percentile instead of the raw marks for preparation of the merit lists. The percentile score is calculated up to seven decimal places to avoid bunching effect and reduce the number of ties. Check the table available below to compare the marks and percentile.

 JEE Main Marks JEE Main Percentile 360 to 310 100 – 99.9872475 309 to 299 99.9855721 – 99.9740296 298 to 288 99.9758912 – 99.9625802 287 to 278 99.9614632 – 99.9442427 277 to 268 99.9409848 – 99.9192962 267 to 258 99.9183654 – 99.8908126 257 to 248 99.8864376 – 99.8484594 247 to 238 99.8451084 – 99.7995904 237 to 228 99.7967979 – 99.7329423 227 to 218 99.7300567 – 99.6547519 217 to 208 99.6488876 – 99.5527320 207 to 198 99.5491948 – 99.4360979 197 to 188 99.4200875 – 99.2895839 187 to 178 99.2647305 – 99.0778181 177 to 168 99.0632970 – 98.8568370 167 to 158 98.8250954 – 98.5571069 157 to 148 98.5310434 – 98.2004095 147 to 138 98.1493996 – 97.7568649 137 to 128 97.6947779 – 97.1764870 127 to 118 97.1384157 – 96.4199013 117 to 108 96.3551149 – 95.4974401 107 to 98 95.4267895 – 94.4012845 97 to 88 94.1947314 – 92.7470911 87 to 78 92.6189146 – 90.6422786 77 to 68 90.4290235 – 87.3418039 67 to 58 87.3418039 – 82.6801638 57 to 48 81.9257190 – 75.3902075 47 to 38 74.1345061 – 64.1130038 37 to 28 62.8883924 – 49.2876291 27 to 18 49.0122870 – 33.0881504 17 to 1 31.3257004 – 9.0775388

JEE Main Normalization Procedure

The JEE Main normalization process is used for comparing candidate scores who appear in multiple session of the examination. To exercise the normalization, candidates’ percentile is taken into the consideration. This is used for ensuring that no candidate is either benefitted or disadvantaged due to the difficulty level of the examination. Check the normalization process below.

Let’s say, candidates appeared in shift 1 = 456789

Therefore, candidates who will score equal to or less than the topper of shift 1 = 456789

Percentile Obtained = 100 (456789/456789) Percentile Obtained = 100

Now, candidates appeared in shift 2 = 345678

So, candidates who will score equal to or less than the topper of shift 1 = 345678

Percentile Obtained = 100 (345678/345678) Percentile Obtained = 100

Suppose, C & D have an equal score 330 and secured the second position in shift 1, E obtains a raw total score of 304 and secured the third position in shift 1 and F secured a raw total score of 304 and gets the second position in shift 2.

After normalization of their score the rank of A, B, C, D, E, and F will be

Candidate A percentile = 100 (456789/456789) = 100

Candidate B percentile = 100 (345678/345678) = 100

Candidate C percentile= 100 (456788/456789) = 99.99823909

Candidate D percentile = 100 (456788/456789) = 99.99823909

Candidate E Percentile = 100 (456786/456789) = 99.99471728

Candidate F Percentile= 100 (345677/345678) = 99.99817147

 Particulars Rank Candidate A Rank 1 Candidate B Rank 1 Candidate C Rank 2 Candidate D Rank 2 Candidate E Rank 4 Candidate F Rank 3

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