National testing agency releases the result, which comprises of the percentile. Candidates obtain the percentile on the basis of their performance in the examination. However, it is easy to calculate the marks from percentile. On this page, we are discussing how to calculate marks from percentile in JEE Main 2020. Percentile scores are scores based on the relative performance of all candidates who appear for the examination. The marks obtained are transformed into a scale ranging from 100 to zero for each session. NTA uses the percentile concept so that normalization procedure can be carried out for compiling the scores for multi session papers.
JEE Main Result 2020 will be announced by the NTA on January 31. The exam was held on January 6, 7, 8, and 9, 2020.
Calculate marks from percentile in JEE Main 2020
NTA normalizes the percentile instead of the raw marks for preparation of the merit lists. The percentile score is calculated up to seven decimal places to avoid bunching effect and reduce the number of ties. Check the table available below to compare the marks and percentile.
| JEE Main Marks | JEE Main Percentile |
| 360 to 310 | 100 – 99.9872475 |
| 309 to 299 | 99.9855721 – 99.9740296 |
| 298 to 288 | 99.9758912 – 99.9625802 |
| 287 to 278 | 99.9614632 – 99.9442427 |
| 277 to 268 | 99.9409848 – 99.9192962 |
| 267 to 258 | 99.9183654 – 99.8908126 |
| 257 to 248 | 99.8864376 – 99.8484594 |
| 247 to 238 | 99.8451084 – 99.7995904 |
| 237 to 228 | 99.7967979 – 99.7329423 |
| 227 to 218 | 99.7300567 – 99.6547519 |
| 217 to 208 | 99.6488876 – 99.5527320 |
| 207 to 198 | 99.5491948 – 99.4360979 |
| 197 to 188 | 99.4200875 – 99.2895839 |
| 187 to 178 | 99.2647305 – 99.0778181 |
| 177 to 168 | 99.0632970 – 98.8568370 |
| 167 to 158 | 98.8250954 – 98.5571069 |
| 157 to 148 | 98.5310434 – 98.2004095 |
| 147 to 138 | 98.1493996 – 97.7568649 |
| 137 to 128 | 97.6947779 – 97.1764870 |
| 127 to 118 | 97.1384157 – 96.4199013 |
| 117 to 108 | 96.3551149 – 95.4974401 |
| 107 to 98 | 95.4267895 – 94.4012845 |
| 97 to 88 | 94.1947314 – 92.7470911 |
| 87 to 78 | 92.6189146 – 90.6422786 |
| 77 to 68 | 90.4290235 – 87.3418039 |
| 67 to 58 | 87.3418039 – 82.6801638 |
| 57 to 48 | 81.9257190 – 75.3902075 |
| 47 to 38 | 74.1345061 – 64.1130038 |
| 37 to 28 | 62.8883924 – 49.2876291 |
| 27 to 18 | 49.0122870 – 33.0881504 |
| 17 to 1 | 31.3257004 – 9.0775388 |
JEE Main Normalization Procedure
The JEE Main normalization process is used for comparing candidate scores who appear in multiple session of the examination. To exercise the normalization, candidates’ percentile is taken into the consideration. This is used for ensuring that no candidate is either benefitted or disadvantaged due to the difficulty level of the examination. Check the normalization process below.
Let’s say, candidates appeared in shift 1 = 456789
Therefore, candidates who will score equal to or less than the topper of shift 1 = 456789
Percentile Obtained = 100 (456789/456789) Percentile Obtained = 100
Now, candidates appeared in shift 2 = 345678
So, candidates who will score equal to or less than the topper of shift 1 = 345678
Percentile Obtained = 100 (345678/345678) Percentile Obtained = 100
Suppose, C & D have an equal score 330 and secured the second position in shift 1, E obtains a raw total score of 304 and secured the third position in shift 1 and F secured a raw total score of 304 and gets the second position in shift 2.
After normalization of their score the rank of A, B, C, D, E, and F will be
Candidate A percentile = 100 (456789/456789) = 100
Candidate B percentile = 100 (345678/345678) = 100
Candidate C percentile= 100 (456788/456789) = 99.99823909
Candidate D percentile = 100 (456788/456789) = 99.99823909
Candidate E Percentile = 100 (456786/456789) = 99.99471728
Candidate F Percentile= 100 (345677/345678) = 99.99817147
| Particulars | Rank |
| Candidate A | Rank 1 |
| Candidate B | Rank 1 |
| Candidate C | Rank 2 |
| Candidate D | Rank 2 |
| Candidate E | Rank 4 |
| Candidate F | Rank 3 |
