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How to calculate marks from percentile in JEE Main 2020

Alexa Tanner by Alexa Tanner
2 years ago
in Education
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How to calculate marks from percentile in JEE Main 2020
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National testing agency releases the result, which comprises of the percentile. Candidates obtain the percentile on the basis of their performance in the examination. However, it is easy to calculate the marks from percentile. On this page, we are discussing how to calculate marks from percentile in JEE Main 2020. Percentile scores are scores based on the relative performance of all candidates who appear for the examination. The marks obtained are transformed into a scale ranging from 100 to zero for each session. NTA uses the percentile concept so that normalization procedure can be carried out for compiling the scores for multi session papers.

JEE Main Result 2020 will be announced by the NTA on January 31. The exam was held on January 6, 7, 8, and 9, 2020.

Calculate marks from percentile in JEE Main 2020

NTA normalizes the percentile instead of the raw marks for preparation of the merit lists. The percentile score is calculated up to seven decimal places to avoid bunching effect and reduce the number of ties. Check the table available below to compare the marks and percentile.

JEE Main Marks JEE Main Percentile
360 to 310 100 – 99.9872475
309 to 299 99.9855721 – 99.9740296
298 to 288 99.9758912 – 99.9625802
287 to 278 99.9614632 – 99.9442427
277 to 268 99.9409848 – 99.9192962
267 to 258 99.9183654 – 99.8908126
257 to 248 99.8864376 – 99.8484594
247 to 238 99.8451084 – 99.7995904
237 to 228 99.7967979 – 99.7329423
227 to 218 99.7300567 – 99.6547519
217 to 208 99.6488876 – 99.5527320
207 to 198 99.5491948 – 99.4360979
197 to 188 99.4200875 – 99.2895839
187 to 178 99.2647305 – 99.0778181
177 to 168 99.0632970 – 98.8568370
167 to 158 98.8250954 – 98.5571069
157 to 148 98.5310434 – 98.2004095
147 to 138 98.1493996 – 97.7568649
137 to 128 97.6947779 – 97.1764870
127 to 118 97.1384157 – 96.4199013
117 to 108 96.3551149 – 95.4974401
107 to 98 95.4267895 – 94.4012845
97 to 88 94.1947314 – 92.7470911
87 to 78 92.6189146 – 90.6422786
77 to 68 90.4290235 – 87.3418039
67 to 58 87.3418039 – 82.6801638
57 to 48 81.9257190 – 75.3902075
47 to 38 74.1345061 – 64.1130038
37 to 28 62.8883924 – 49.2876291
27 to 18 49.0122870 – 33.0881504
17 to 1 31.3257004 – 9.0775388

JEE Main Normalization Procedure

The JEE Main normalization process is used for comparing candidate scores who appear in multiple session of the examination. To exercise the normalization, candidates’ percentile is taken into the consideration. This is used for ensuring that no candidate is either benefitted or disadvantaged due to the difficulty level of the examination. Check the normalization process below.

Let’s say, candidates appeared in shift 1 = 456789

Therefore, candidates who will score equal to or less than the topper of shift 1 = 456789

Percentile Obtained = 100 (456789/456789) Percentile Obtained = 100

Now, candidates appeared in shift 2 = 345678

So, candidates who will score equal to or less than the topper of shift 1 = 345678

Percentile Obtained = 100 (345678/345678) Percentile Obtained = 100

Suppose, C & D have an equal score 330 and secured the second position in shift 1, E obtains a raw total score of 304 and secured the third position in shift 1 and F secured a raw total score of 304 and gets the second position in shift 2.

After normalization of their score the rank of A, B, C, D, E, and F will be

Candidate A percentile = 100 (456789/456789) = 100

Candidate B percentile = 100 (345678/345678) = 100

Candidate C percentile= 100 (456788/456789) = 99.99823909

Candidate D percentile = 100 (456788/456789) = 99.99823909

Candidate E Percentile = 100 (456786/456789) = 99.99471728

Candidate F Percentile= 100 (345677/345678) = 99.99817147

Particulars Rank
Candidate A Rank 1
Candidate B Rank 1
Candidate C Rank 2
Candidate D Rank 2
Candidate E Rank 4
Candidate F Rank 3
Alexa Tanner

Alexa Tanner

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